Matematika

Pertanyaan

tentukan hasil dari(tanpa menghitung satu persatu)
A. 1+3+5+7+9+...+99
B. 1-2+3-4+5-6+7-8+...-10
C. –100-99-98-...-2-1-0+1+2+...+48+49+50

2 Jawaban

  • A.
    A = 1
    B = 3-1 = 2

    Banyak suku :
    = 99/2
    = 49,5 (50)

    S50 :
    = n/2 x (a + Un)
    = 50/2 x (1 + 99)
    = 25 x 100
    = 2500

    B.
    1-2 = -1
    3-4 = -1
    .. - .. = -1
    9-10 = -1

    Banyak kali penjumlahan :
    = 10 :2
    = 5

    Maka hasilnya :
    = -1 x 5
    = -5

    C.
    A = -100
    B = -99 - (-100) = 1

    Banyak suku :
    = 100 + 1 + 50
    = 151

    S151 :
    = n/2 (a + Un)
    = 151/2 (-100 + 50)
    = 75,5 x (-50)
    = -3775
  • Mapel : Matematika
    Kelas : IX SMP
    Bab : Barisan dan deret

    Pembahasan :
    Un = 2n - 1
    99 = 2n - 1
    2n = 100
    n = 50

    1 + 3 + 5 + 7 + ... + 99 = n²
    1 + 3 + 5 + 7 + ... + 99 = 50²
    1 + 3 + 5 + 7 + ... + 99 = 2500

    ————————————————
    1 - 2 + 3 - 4 + ... - 10
    = -1 - 1 - 1 - 1 - ... - 1
    = -(1 + 1 + ... + 1)
    = -(10/2)
    = -5

    ————————————————
    Un = 50
    a + (n - 1)b = 50
    -100 + n - 1 = 50
    n - 101 = 50
    n = 151

    -100 - 99 - 98 - ... + 50
    = S151
    = 151/2(-100 + 50)
    = 151/2(-50)
    = -3775

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