tentukan nilai bentuk aljabar jika nilai x = 16 dan y = 64. a. x½ b. y⅓ c. x¼ + y -⅔ d. x -½ - y -¹/6

a)
x^1/2
= √x
= √16
= 4

b)
y^1/3
= ^3 √64
= 4


c)
x^1/4 + y^-2/3
= ^4 √16 + (64)^-2/3
= 2 + (4^3)^-2/3
= 2 + 4^-2
= 2 + 1/4²
= 2 + 1/16
= 2 1/16


d)
x^-1/2 - y^-1/6
= 1/√x - 1/(y)^1/6
= 1/√16 - 1/(64)^1/6
= 1/4 - 1/(2^6)^1/6
= 1/4 - 1/2^1
= 1/4 - 1/2
= 1/4 - 2/4
= - 1/4