1.(3m-2n)⁴ 2.(4a-3b)³
Matematika
frd15
Pertanyaan
1.(3m-2n)⁴
2.(4a-3b)³
2.(4a-3b)³
1 Jawaban
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1. Jawaban SadonoSukirno
gunakan segitiga pascal
(3m - 2n)⁴
= (3m)⁴ - 4(3m)³(2n) + 6(3m)²(2n)² + 4(3m)(2n)³ + (2n)⁴
= 81m⁴ - 216m³n + 216m²n² + 96mn³ + 16n⁴
(4a - 3b)³
= (4a)³ - 3(4a)²(3b) + 3(4a)(3b)² - (3b)³
= 64a³ - 144a²b + 108ab² - 27b³