Pr fisika ttg gerak lurus sma kelas X. tolong dibantu yaa :)

x=[tex] 5t^{2} [/tex] +1
untuk t=3 -> [tex] 5.(3)^{2}+1 = 46 [/tex]
untuk t=2 -> [tex] 5.(2)^{2} +1 = 21[/tex]

v=46-21 = 25 m/s

r= 5t^2 + 1
v=(r2-r1) / (t2-t1)
t1=2 => r1= 5×2^2 +1 = 21
t2=3 => r2= 5×3^2 + 1= 46
v= (46-21) / (3-2) = 25 m/s