Tolong yaaaaa..... Udah 3 kali aku tanyain nihhhh

1)
a) 6ab : (-3a) = 6/-3 × a/a × b
= -2b
b) (-3pqr) : 3p²q = -3/3 × p/p² × q/q × r
= -1 × 1/p × 1 × r
= -r/p
c) (-½x)³ : (-⅔x)² = (-1/8)x³ : (-4/9)x²
= (-1/8):(-4/9) × x³/x²
= (-1/8)×(-9/4) × x
= (9/32)x

2) (4ab³ - 3a²b) : 2ab = ab(4b² - 3a) : 2ab
= (4b² - 3a) : 2
= (4(5)² - 3(-2)) : 2
= (100 + 6) : 2
= 106 : 1
= 53