kerucut volume 2512 tinggi 24 berapa a luas permukaan b jari jari

B. V = 1/3 × phi × r^2 × t

2.512 = 1/3 × 3,14 × r^2 × 24

2.512 = 1 × 3,14 × r^2 × 8

2.512 = 25,12 × r^2

r^2 = 2.512 ÷ 25,12

r^2 = 100 (diakarkan pangkat 2)

r^2 = 10


A. S = r^2 + t^2

= 10^2 + 24^2

= 100 + 576

= 676 (diakarkan pangkat 2)

= 26



L = phi × r^2 + phi × r × s

= 3,14 × 10^2 + 3,14 × 10 × 26

= 3,14 × 100 + 816,4

= 314 + 816,4

= 1.130,4