1. sin 2x = cos (x+15) 2. 2sin^2x +sinx-1=0 3. cos^2x + sin (90+x) -2 = 0 4. 3 tan^2+ 5 tanx - 2 mohon bantuannnyaaa
Matematika
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Pertanyaan
1. sin 2x = cos (x+15)
2. 2sin^2x +sinx-1=0
3. cos^2x + sin (90+x) -2 = 0
4. 3 tan^2+ 5 tanx - 2
mohon bantuannnyaaa
2. 2sin^2x +sinx-1=0
3. cos^2x + sin (90+x) -2 = 0
4. 3 tan^2+ 5 tanx - 2
mohon bantuannnyaaa
1 Jawaban
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1. Jawaban DB45
Persamaan trigonometri
1. sin 2x = cos (x + 15)
sin (2x) = sin { 90 - (x +15)}
2x = 90 - x - 15
3x = 75
x = 25
2.
2 sin² x + sin x - 1= 0
(2 sin x - 1)(sinx + 1) = 0
2 sin x - 1 = 0 atau sin x + 1 = 0
sin x = 1/2 atau sin x = -1
.
sin x = 1/2 = sin 30 = sin 150
x = 30, 150
sin x = 1 = sin 270
x = 270
HP x = (30, 150, 270)
3.
cos² x + sin(90 + x) - 2 = 0
cos² x + cos x - 2 = 0
(cos x -1)(cos x + 2) = 0
cos x - 1= 0 atau cos x + 2 = 0
cos x = 1 atau cos x = - 2 (TM)
cos x = 1 = cos 90
x = 0
4.
3 tan² x + 5 tan x - 2= 0
(3tan x -1) ( tan x + 2) = 0
tan x = 1/3 atau tan x = - 2