Volume sebuah tabung 4.710cm³,tinggi 15 cm dan phi=3,14. Tentukan: a. Panjang jari2 b. Luas selimut c. Luas permukaan

A. V = phi × r^2 × T

4.710 = 3,14 × r^2 × 15

4.710 = 47,1 × r^2

r^2 = 4.710 ÷ 47,1

r^2 = 100 (diakarkan pangkat 2)

r^2 = 10 cm

B. L = 2 × phi × r × t

= 2 × 3,14 × 10 × 15

= 6,28 × 150

= 942 cm^2

C. L = 2 × phi × r × ( r + t )

= 2 × 3,14 × 10 × (10 + 15)

= 2 × 3,14 × 10 × 25

= 6,28 × 250

= 1.570 cm^2