tentukan f (x) jika diketahui f'(x)=-x^2+2x-3 dan f (3)=0

f(3)=3^2+2.3
=9+6
=15
moga membntu jdkn jwbn trbaik ya mksh

Integral

f(x) = ∫ f '(x) dx
f(x)= ∫ -x² + 2x - 3 dx
f (x) = - 1/3 x³ + x² - 3x + c
f (3) = 0
- 1/3 (3³) + (3)² - 3(3) + c = 0
-9 + 9 - 9 + c =0
c = 9

f(x) = - 1/3 x³ + x² - 3x + 9