Matematika

Pertanyaan

2log 3 = a dan 3 log 5 = b maka 4 long 15

1 Jawaban

  • Logaritma

    ⁴log 15
    = ³log 15/³log 4
    = ³log(5 ×3) / ³log (2²)
    =( ³log 5 + ³log 3) / (2 . ³log 2)
    = (b + 1) / (2 . 1/(²log3))
    = (b + 1) / (2/a)
    = (b + 1) × a/2
    = (a(b +1))/2

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