brp hasilnya? mohon dibantu ya
Matematika
pipi34
Pertanyaan
brp hasilnya?
mohon dibantu ya
mohon dibantu ya
2 Jawaban
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1. Jawaban margaretcesilia
(a^-5 b^8 c^-2)^2
= a^-10 b^16 c^-4
semoga membantu, ^-^ -
2. Jawaban Sutr1sn0
[(a^(-4)b^2c)/(ab^(-6)c^3)]^2
= [a^(-4 - 1) b^(2 - (-6)) c^(1 - 3)]^2
= [a^(-5) b^(2 + 6) c^(-2)]^2
= [a^(-5) b^8 c^(-2)]^2
= [a^(-5 × 2) b^(8 × 2) c^(-2 × 2)]
= [a^(-10) b^16 c^(-4)]
= (1/a)^10 b^16 (1/c)^4
= (b^16)/(a^10 c^4)