Matematika

Pertanyaan

brp hasilnya?
mohon dibantu ya
brp hasilnya? mohon dibantu ya

2 Jawaban

  • (a^-5  b^8  c^-2)^2

    = a^-10  b^16  c^-4




    semoga membantu, ^-^


  • [(a^(-4)b^2c)/(ab^(-6)c^3)]^2
    = [a^(-4 - 1) b^(2 - (-6)) c^(1 - 3)]^2
    = [a^(-5) b^(2 + 6) c^(-2)]^2
    = [a^(-5) b^8 c^(-2)]^2
    = [a^(-5 × 2) b^(8 × 2) c^(-2 × 2)]
    = [a^(-10) b^16 c^(-4)]
    = (1/a)^10 b^16 (1/c)^4
    = (b^16)/(a^10 c^4)