tan (2x-π/6) = tan π/3

ππPersmaan trigonomteri

tan (2x - π/6) = tan (π/3)

2x - π/6 = π/3 + k. π
2x = π/6 + π/3  + k. π
2x = π/2 + k. π
x = π/4  + k. π/2
k =  0,1,2,3....

k = 0 --> x = π/4
k = 1 --> x = 3π/4
k = 2 --> x = 5π/4
k = 3 --> x = 7π/4
k = 4 --> x = 9π/4
jika  interval  0 < x< 2π

x = (π/4, 3π/4, 5π/4, 7π/4)