jika 2 pangkat p × 3 pangkat q × 5 pangkat r = 1.125.000 berapakah nilai p,q,r?

p=3
q=2
r=6
............

2^p × 3^q × 5^r = 1.125.000
2^p × 3^q × 5^r = 1.125 × 1.000
2^p × 3^q × 5^r = (1.000 + 125) × 10^3
2^p × 3^q × 5^r = (10^3 + 5^3) × 10^3
2^p × 3^q × 5^r = ((2 × 5)^3 + 5^3) × (2 × 5)^3
2^p × 3^q × 5^r = (2^3 × 5^3 + 5^3) × (2 × 5)^3
2^p × 3^q × 5^r = 5^3 × ( 2^3 + 1) × 2^3 × 5^3
2^p × 3^q × 5^r = 5^3 × ( 8 + 1 ) × 2^3 × 5^3
2^p × 3^q × 5^r = 5^3 × 9 × 2^3 × 5^3
2^p × 3^q × 5^r = 5^3 × 3^2 × 2^3 × 5^3
2^p × 3^q × 5^r = 5^(3+3) × 3^2 × 2^3
2^p × 3^q × 5^r = 5^6 × 3^2 × 2^3
2^p × 3^q × 5^r = 2^3 × 3^2 × 5^6

p = 3
q = 2
r = 6

Jawaban ada di atas
Terimakasih :)