1) ( x^2 + 2x - 5 ) + ( 3x - 2 ) = 2) ( 2x + 3 ) - (-2x - 4 ) = 3) 3( x^2 - 3x ) = 4) ( x + 5 ) ( x - 5 ) = 5) ( 2x + 3 ) ( x - 5 ) =
Matematika
sriyonoismailhadi
Pertanyaan
1) ( x^2 + 2x - 5 ) + ( 3x - 2 ) =
2) ( 2x + 3 ) - (-2x - 4 ) =
3) 3( x^2 - 3x ) =
4) ( x + 5 ) ( x - 5 ) =
5) ( 2x + 3 ) ( x - 5 ) =
2) ( 2x + 3 ) - (-2x - 4 ) =
3) 3( x^2 - 3x ) =
4) ( x + 5 ) ( x - 5 ) =
5) ( 2x + 3 ) ( x - 5 ) =
1 Jawaban
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1. Jawaban safiraaiueo
[tex]Penyelesaian : 1) ( x^{2} + 2x - 5 ) + ( 3x - 2 ) = x^{2} + 2x - 5 + 3x - 2 = x^{2} + 5x - 7 2) ( 2x + 3 ) - ( -2x - 4 ) = 2x + 3 + 2x + 4 = 4x + 7 3) 3( x^{2} - 3x ) = 3 x^{2} - 9 x^{2} 4) ( x + 5 ) ( x - 5 ) = x^{2} - 5x + 5x - 25 = x^{2} - 25 5) ( 2x + 3 ) ( x - 5 ) = 2 x^{2} - 10x + 3x - 15 = 2 x^{2} - 7x - 15[/tex]