Menentukan hp dari persamaan nilai mutlak 1. (x + 1) = 1 2. (5 - 2/3x) - 13 = 15 3. (3x - 1) = x - 2 4. (3x/x - 1/-7) = 2 5. (9x - 2) = (11x + 3) Tolong dijawab

1.(x+1)=1
-(x+1)=1
-x-1=1
-x=1+1
x=2/-1
x=-2
(x+1)=1
x=1-1
x=0
HP (-2,0)
3.-(3x-1)=x-2
-3x+1=x-2
-3x-x=-2-1
-4x=-3
x=-3/-4
x=3/4
(3x-1)=x-2
3x-x=-2+1
2x=-1
x=-1/2
HP(3/4,-1/2)
5.(9x-2)^2=(11x+3)^2
81x^2-36x+4= 121x^2+66x+9
81x^2-121x^2-36x-66x+4-9
-40x^2-102x-5
40x^2+102x+5
(20x+1) (2x+5)
20x=-1
x=-1/20
2x=-5
x=-5/2
HP (-1/20,-5/2)
Maaf kalok salah