Matematika

Pertanyaan

1. jika 6x^2+36x+m=6(x+n)^2 maka nilai m adalah
2. jika x^2-y^2=120 dan x+y=30 maka xy =

jawab dua duanya yaa.

1 Jawaban

  • 1) 6x^2 + 36x + m = 6(x + n)^2
    6x^2 + 36x + m = 6(x^2 + 2nx + n^2)
    6x^2 + 36x + m = 6x^2 + 12nx + 6n^2

    Koefisien x
    36 = 12n => n = 3

    Konstanta
    m = 6n^2 = 6(3)^2 = 6(9) = 54

    2) x^2 - y^2 = 120
    (x + y)(x - y) = 120
    30 (x - y) = 120
    x - y = 4

    x + y = 30
    x - y = 4
    -------------- +
    2x = 34 => x = 17

    x + y = 30 => 17 + y = 30 => y = 13

    xy = 17(13) = 221

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