Matematika

Pertanyaan

selesaikan dengan metode substitusi!
x+8=2(y+3)
x-4y=4(x-2y+2)
bantuin dong

1 Jawaban

  • x+8 = 2(y+3)
    x+8 = 2y + 6
    x-2y= 6-8
    x-2y= -2

    x-4y=4(x-2y+2)
    x-4y=4x-8y+8
    x-4y-4x-8y=8
    -3x-12y=8
    3x-12y= -8

    x-2y = -2 x3
    3x-12y = -8 x1

    3x-6y= -6
    3x-12y= -8
    _________-
    6y = 2
    y = 2/6
    y = 1/3

    x-2y = -2. x6
    3x-12y= -8. x1

    6x-12y = -12
    3x-12y = -8
    _________+
    9x = -20
    x = -20/9
    x = -2 ²/9

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