selesaikan dengan metode substitusi! x+8=2(y+3) x-4y=4(x-2y+2) bantuin dong
Matematika
indah14007
Pertanyaan
selesaikan dengan metode substitusi!
x+8=2(y+3)
x-4y=4(x-2y+2)
bantuin dong
x+8=2(y+3)
x-4y=4(x-2y+2)
bantuin dong
1 Jawaban
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1. Jawaban lintangannisa21
x+8 = 2(y+3)
x+8 = 2y + 6
x-2y= 6-8
x-2y= -2
x-4y=4(x-2y+2)
x-4y=4x-8y+8
x-4y-4x-8y=8
-3x-12y=8
3x-12y= -8
x-2y = -2 x3
3x-12y = -8 x1
3x-6y= -6
3x-12y= -8
_________-
6y = 2
y = 2/6
y = 1/3
x-2y = -2. x6
3x-12y= -8. x1
6x-12y = -12
3x-12y = -8
_________+
9x = -20
x = -20/9
x = -2 ²/9