1. Nilai t yang memenuhi kesamaan x³-7x+6=(x+3)(x-2)(x-t) 2. 5x²-2x+3=ax²+(b+c)x+ 7(b-c) maka a+8b-6c

Kesamaan aljabar

1.
x³  - 7x + 6 = (x+3)(x-2)(x-t)
..
6 = 3(-2)(-t)
6 = 6t
t = 1
..

2.
5x² -2x + 3 = ax² + (b+c) x + 7(b-c)
.
a = 5
b+ c = - 2
7(b-c) = 3 --> b - c = 3/7
..
b + c = -2
b - c = 3/7
jumlahkan
2b = - 11/7
b = - 11/14
.
b+ c = -2
b - c=  3/7
kurangkan
2c = -17/7
c = -17/14

a + 8b - 6c= (5) + 8(3/7)  -6(-17/4)
= 5 + 24/14 + 102/14
= 5 + 126/14
= 5 + 9
= 14