Asam sulfat (Mr=98) dalam larutan asam sulfat 10% massa,mempunyai fraksi mol sebesar...(Mr air = 18)

asam sulfat (H2SO4)
Mr = 98
larutan asam sulfat 10% --> 10 gram H2SO4/100 gram air
Mr air = 18

mol H2SO4 = 10 gram / 98 = 0.102 mol
mol air = 100 gram / 18 =5.6 mol
frakai mol H2SO4 = 0.102 mol/(0.102 mol +5.6 mol) = 0.102 mol / 5.6576 mol = 0.018