tentukan hasil dari (tanpa menghitung satu pessary)a.1+3+5+7+9...+99b.1–2+3–4+5–6+7–8+...–100c.–100–99–98–...–2–1–0+1+2+...+48+49+50. please jwb dg caranya

a•
1 + 3 + 5 + ... + 99 ----> 50 suku (n = 50)
= (1 + 99) + (3 + 97) + ... + (49 + 51)
= 100 × 50/2
= 2500

b•
(1 - 2) + (3 - 4) + ... + (99 - 100) ---> n = 100
= (-1) × 100/2
= -50

c•
-100 - 99 - ... - 50 - 49 ... - 0 + 1 + ... + 49 + 50
= -100 - 99 - 98 - ... - 51 + 0
= -(100 + 99 + 98 + ... + 51) ---> n = 50
= -((100 + 51) + (99 + 52) + ... + (76 + 75))
= -(151 × 50/2)
= -(151 × 25)
= -3775

Kategori: Matematika
Materi: Deret
Kelas: IX SMP
Kata kunci: Pola Deret


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