Diketahui fungsi f(x) = 3x − 1 dan g(x) = 2x² + 3. Nilai dari komposisi fungsi (g o f)(1) =.... point gede loh...

(gof)(x) = g(f(x))
= 2(3x - 1)² + 3
= 2(9x² - 6x + 1) + 3
= 18x² - 12x + 5

(gof)(1) = (g(f(1))
= 18(1)² - 12(1) + 5
= 18 - 12 + 5
= 11

Komposisi fungsi

f(x)= 3x - 1 , g(x)= 2x² + 3
f(1) = 3(1) - 1
f(1) = 2

gof(1) = g(2)= 2(2²) + 3 = 8+3
gof(1) = 11