Matematika

Pertanyaan

Bentuk 2 : √2 +1 ekuivalen dengan.. .

1 Jawaban

  • [tex]\frac{2}{\sqrt{2}+1} = \frac{2 . (\sqrt{2}-1)}{(\sqrt{2}+1)(\sqrt{2}-1)} = \frac{2\sqrt{2}-2}{2-1} = \sqrt{2} - 1\\ [/tex]

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