1) log a½ - log b½ - ½ log ab = 2) 1/5 log 625 + 64 log 1/16 + 4³ 25 log 5 =
Matematika
ikaamalia1604
Pertanyaan
1) log a½ - log b½ - ½ log ab =
2) 1/5 log 625 + 64 log 1/16 + 4³ 25 log 5 =
2) 1/5 log 625 + 64 log 1/16 + 4³ 25 log 5 =
1 Jawaban
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1. Jawaban Anonyme
Bab Logaritma
Matematika SMA Kelas X
1] log a^(1/2) - log b^(1/2) - 1/2 . log ab = 1/2 . log a - 1/2 . log b - 1/2 . log ab
= 1/2 (log (a : b : ab)
= 1/2 log 1/b²
= 1/2 . log b⁻²
= (-2) . 1/2 . log b
= - log b
2] ^(1/5)log 625 + ⁶⁴log (1/16) + 4³ . ²⁵log 5
= - ⁵log 5⁴ + (- 1/6) ²log 2⁻⁴ + 64 . (-1) ⁵log 5
= -4 - (1/6) x (-4) - 64
= -4 + 1/3 - 64
= -67 2/3