bantu nomor 7 ya kak

|1 ... 1 ... 3| .. 1 .. 1
|x .. y ... 2| .. x .. y
|1 .. 2 ... 2| .. 1 ... 2

|A| = (1.y.2 + 1.2.1 + 3.x.2) - (3.y.1 + 1.2.2 + 1.x.2)
0 = (2y + 2 + 6x) - (3y + 4 + 2x)
0 = -y + 4x - 2
y = 4x - 2
m = 4

Persamaan garis melalui (2,3) dan m = 4
y - y1 = m(x - x1)
y - 3 = 4(x - 2)
y - 3 = 4x - 8
y = 4x - 5
-4x + y + 5 = 0
4x - y - 5 = 0