Matematika

Pertanyaan

tolong ya no 4 (a .b .c)
tolong ya no 4 (a .b .c)

1 Jawaban

  • A. 1 +3 +5 +7 +9
    99+97 +95 +93 +91
    =100+100+100+100+100
    =100×50÷2=250
    B. 1-2 +3-4 +5-6 +7-8 +... 100
    (1-2) + (3-4)+ (5-6) + (7-8)+... (99-100)
    = -1 + -1 + -1 + -1 +... -1
    = -1×50= -50
    c. bilangan negatif=
    -100-99-98...-2 -1
    -1 -2 -3 ...-99-100
    =-101-101-101..-101-101
    = -101×100÷50= -5050
    Bilangan positif=
    1 +2 +3 +4+... +50
    50+49+48+47... +1
    =51 +51 +51+51... +51
    =51×50÷2=1275
    bilangan negatif+bilangan positif
    = -5050 + 1275
    = -3775