Tolong yg bisa di jawab ya.. kalo ngga bisa dari no 1 langsung no 6 aja

baru bisa segitu dulu

1) (a^2*b^3)/(a*b) × (a^(-5)*b^4)/(a^2*b^(-1))
= (a^(2 - 1)*b^(3 - 1)) × (a^(-5 - 2)*b^(4 - (-1)))
=a*b^2 × a^(-7)*b^5 = a^(-6)*b^7

2) (a^2*b)^3 × (a^(-2)*b)^5 = a^6*b^3 × a^(-10)*b^5 = a^(-4)*b^8

3) (a^5*b^(-2))^3 ÷ (a^3*b^(-1))^2 = a^15*b^(-6) ÷ a^6*b^(-2) = a^9*b^(-4)

4) a^3*b^(-2) = 2^3 × 5^(-2) = 8 × 1/25 = 8/25

5) (p^2/q^(-1))^3 = p^6/q^(-3) = 5^6/3^(-3)
= 5^6 × 3^3 = 15625 × 9 = 140625

6) (2/5)^2 × (5^3/4) ÷ (8/5)^(-3)
= 4/25 × 125/4 ÷ 125/512 = 5 ÷ 125/512 = 512/25

Perintah soal no. 7 dan 8 terpotong sebagian.