Hitunglah nilai x (jika ada) yang memenuhi persamaan nilai mutlak berikut. Jika tidak ada nilai x yang memenuhi berikan alasannya. 1. | 4-3x | = |-4| 2. 2 | 3x-

1. | 4-3x | = |-4|
=> 4- 3x = -4
=> 3x = 8
=> x = 8/3
atau
=> 4-3x = 4
=> -3x = 0
=> x = 0

Hp ={0,8/3}

2.2 | 3x-8 | = 10
=> | 3x-8 | = 5
=> 3x -8 = 5
=> 3x = 13
=> x = 13/3
atau
=> 3x -8 = -5
=> 3x = 3
=> x =1
Hp = {1,13/3}

3.2x | 3x-8 | = -4
=> 3x- 8 = -2/x
=> 3x² -8x +2 =0
=> 8 +/- √64 -4(3)*2 /2(3)
=> 8 +/- √64 -24 / 6
=> 8+/- √40 /6
=> x1 = 8+√40 /6
=> x2 = 8-√40 /6

4. 5 | 2x-3 | = 2 | 3-5x |
=>5 (2x-3 )²= 2 (3-5x )²
=> 5 ( 4x² - 12x + 9) = 3(25x² - 30x+9)
=> 20x² - 60x + 45 = 75x² - 90x + 27
=> 55x² -30x - 18