mtk integral fungsi aljabar tolong di jawab no.10 pakai cara

Integral
cara 1
ₐᵇ∫f(x) dx = F(b) - F(a)
.
₀⁴∫ f(x) dx  = 2 --> F(4) - F(0) = 2
₂⁴∫ 2. f(x) dx = 2 -> 2. F(4) - 2 F(2) = 2 --> F(4) - F(2) = 1
.eliminasi

F(4) - F(0) = 2
F(4) - F(2) = 1
kurangkan
F(2) - F(0) = 1 --> ₀²∫ f(x) dx = F(2) - F(0) = 1

cara II
₀⁴∫ f(x) dx = ₀²∫ f(x) dx + ₂⁴∫f(x)  dx
₀²∫  f(x) dx = ₀⁴∫ f(x) dx - ₂⁴∫f(x) dx
₀²∫ f(x) dx = 2 - 1 = 1