jika (akar 3) pangkat 5 dikali 9 pangkat 2=(3) pangkat a dikali 3 akar 3, maka a=

akar pangkat ½
^ tanda pangkat
(√3)^5 × 9^2 = 3^a × 3√3
(3^½)^5 × (3^2)^2 = 3^a × 3(3^½)
3^(½×5) × 3^(2×2) = 3^a × 3^(1+½)
3^5/2 × 3^4 = 3^a × 3^(3/2)
3^(5/2 + 4) = 3^(a + 3/2)
5/2 + 4 = a + 3/2 kalikan dengan 2
5 + 8 = 2a + 3
13 = 2a + 3
13 - 3 = 2a
10 = 2a
a = 10/2 = 5