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Matematika
aldhyshoe
Pertanyaan
Tlong!!
Bgi yg bisa, tlong d jwab...
Please..
Bgi yg bisa, tlong d jwab...
Please..
1 Jawaban
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1. Jawaban Wiraa
Penyelesaian:
[tex]( \frac{2^-1 . a^3 . b^-4}{4a^-2 . b})^-1 [/tex]
= [tex]( \frac{2^-1 . a^3 . b^-4}{2^2 . a^-2 . b})^-1 [/tex]
= (2^-3 . a^5 . b^-5)^-1
= 2^3 . a^-5 . b^5
= 8(b/a)^5 (E).
[tex] \frac{a^-2 - b^-2}{a^-1 - b^-1} [/tex]
= [tex] \frac{(a^-1 - b^-1)(a^-1 + b^-1)}{a^-1 - b^-1} [/tex]
= a^-1 + b^-1
= 1/a + 1/b
= a+b / ab (C).