Matematika

Pertanyaan

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1 Jawaban

  • Penyelesaian:

    [tex]( \frac{2^-1 . a^3 . b^-4}{4a^-2 . b})^-1 [/tex]
    = [tex]( \frac{2^-1 . a^3 . b^-4}{2^2 . a^-2 . b})^-1 [/tex]
    = (2^-3 . a^5 . b^-5)^-1
    = 2^3 . a^-5 . b^5
    = 8(b/a)^5  (E). 

    [tex] \frac{a^-2 - b^-2}{a^-1 - b^-1} [/tex]
    = [tex] \frac{(a^-1 - b^-1)(a^-1 + b^-1)}{a^-1 - b^-1} [/tex]
    = a^-1 + b^-1
    = 1/a + 1/b
    = a+b / ab  (C).